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Janet Charlton's HOLLYWOOD

TOM CRUISE’S MISSION IMPOSSIBLE IS FINDING A GIRLFRIEND

This is actress Rebecca Ferguson and she might be the reason Tom Cruise moved to the UK. Tom took a liking to her when he saw her in The White Queen and hired her as his leading lady in his last Mission Impossible-Rogue Nation movie in 2015. She was a newcomer when she was called to his office expecting to audition, and shocked when he told her it wasn’t necessary “You’ve got the job!” Sound familiar? That’s how Tom met Nicole Kidman and Rebecca has been described as a young version of Nicole. She played a kick-ass character who did almost as many stunts as Tom – but it turned out she was living with a boyfriend and not available for romancing at that time. Fast forward to 2017 and her character has been written into the new Mission Impossible script and coincidentally she has broken up with her boyfriend! Stay tuned.

Photo Credit: Pacific Coast News

Join the Conversation

  1. morekissespls

    He is a scary cult robot. I believe he has mental issues at this point. Seriously. I wouldn’t trust him alone with my dog.

  2. kissy

    if she aint nuts now she will brainwashed in time by tomm himself.

  3. Becca

    It’s mandatory that Lil Tommy’s fake girlfriend must be a $cientologist.
    Ferguson isn’t!

  4. Diva

    Run Rebecca, Run

  5. ana

    Actually, she has a boyfriend

    https://www.youtube.com/watch?v=tmiXX-uennI

  6. noblecascade

    does that Scientology bunch allow him to have sex? Just wondered since they control all things.

  7. Sal Delvechio the barber

    What woman in her right mind would date a Scientology freak?

  8. ah-yuck

    His only “impossible mission” is getting out of that demented cult who’s controlling him.

  9. beachy

    Another fake romance for a fake guy. Add to that that he is irrelevant and you get a big fat “who cares”?

  10. morekissespls

    Cruise is never available for romancing when it comes to women.

    Why doesn’t he just leap out of the closet and be who he really is?